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2x^2-5x-7500=0
a = 2; b = -5; c = -7500;
Δ = b2-4ac
Δ = -52-4·2·(-7500)
Δ = 60025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{60025}=245$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-245}{2*2}=\frac{-240}{4} =-60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+245}{2*2}=\frac{250}{4} =62+1/2 $
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